यदि (f(x)=\frac{1}{x-2}) और (g(x)=\frac{1}{x+4}) हैं, तो ((f-g)(x)) क्या है?
If (f(x)=\frac{1}{x-2}) and (g(x)=\frac{1}{x+4}), what is ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
B. (\frac{6}{(x-2)(x+4)})
Concept
((f-g)(x)=\frac{x+4-(x-2)}{(x-2)(x+4)}=\frac{6}{(x-2)(x+4)}). Keep numerator signs carefully while using a common denominator.
Why this answer is correct
The correct answer is B. (\frac{6}{(x-2)(x+4)}). ((f-g)(x)=\frac{x+4-(x-2)}{(x-2)(x+4)}=\frac{6}{(x-2)(x+4)}). Keep numerator signs carefully while using a common denominator.
Exam Tip
((f-g)(x)=\frac{x+4-(x-2)}{(x-2)(x+4)}=\frac{6}{(x-2)(x+4)})। समान हर बनाते समय अंश के चिन्ह ध्यान से रखें।
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