यदि (f(x)=\frac{1}{x-2-1}) और (g(x)=x+2) हों, तो ((f+g)(x)) के domain से कौन से मान हटेंगे?
If (f(x)=\frac{1}{x-2-1}) and (g(x)=x+2), which values are excluded from the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. (x=-1) और (x=1)(x=-1) and (x=1)
Concept
(x-2-1=(x-1)(x+1)), so the denominator is zero at (x=1) and (x=-1). Values making the denominator zero are excluded from the domain.
Why this answer is correct
The correct answer is A. (x=-1) और (x=1) / (x=-1) and (x=1). (x-2-1=(x-1)(x+1)), so the denominator is zero at (x=1) and (x=-1). Values making the denominator zero are excluded from the domain.
Exam Tip
(x-2-1=(x-1)(x+1)), इसलिए denominator zero (x=1) और (x=-1) पर होता है। domain में denominator zero values हटती हैं।
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