यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{x-2+1}{x-2+2}) से दिया गया है तो परिसर क्या है?
If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{x-2+1}{x-2+2}), what is the range?
Explanation opens after your attempt
Correct Answer
A. \(\left[\frac{1}{2},1\right\))
Concept
The value is \(1-\frac{1}{x^2+2}\), so the minimum is \(\frac{1}{2}\) and (1) is never attained. The range is \(\left[\frac{1}{2},1\right\)).
Why this answer is correct
The correct answer is A. \(\left[\frac{1}{2},1\right\)). The value is \(1-\frac{1}{x^2+2}\), so the minimum is \(\frac{1}{2}\) and (1) is never attained. The range is \(\left[\frac{1}{2},1\right\)).
Exam Tip
मान \(1-\frac{1}{x^2+2}\) है, इसलिए न्यूनतम \(\frac{1}{2}\) और (1) कभी नहीं मिलता। परिसर \(\left[\frac{1}{2},1\right\)) है।
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