यदि \(\binom{n}{1}+\binom{n}{2}=36\) है तो (n) का मान क्या है?
If \(\binom{n}{1}+\binom{n}{2}=36\), what is the value of (n)?
Explanation opens after your attempt
B. (8)
Concept
It gives (n+\frac{n(n-1)}{2}=36). Putting (n=8) gives (8+28=36).
Why this answer is correct
The correct answer is B. (8). It gives (n+\frac{n(n-1)}{2}=36). Putting (n=8) gives (8+28=36).
Exam Tip
यह (n+\frac{n(n-1)}{2}=36) देता है। (n=8) रखने पर (8+28=36) मिलता है।
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