यदि \(\binom{n}{1}+\binom{n}{2}=136\) है तो (n) का मान क्या है?
If \(\binom{n}{1}+\binom{n}{2}=136\), what is the value of (n)?
Explanation opens after your attempt
Correct Answer
B. (16)
Concept
It gives (\frac{n(n+1)}{2}=136). Putting (n=16) gives (136).
Why this answer is correct
The correct answer is B. (16). It gives (\frac{n(n+1)}{2}=136). Putting (n=16) gives (136).
Exam Tip
यह (\frac{n(n+1)}{2}=136) देता है। (n=16) रखने पर (136) मिलता है।
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