यदि \( \binom{11}{r}=\binom{11}{r-3} \), तो ( r ) का मान क्या है?

If \( \binom{11}{r}=\binom{11}{r-3} \), what is the value of ( r )?

Explanation opens after your attempt
Correct Answer

B. (7)

Step 1

Concept

By symmetry, (r+(r-3)=11), so (r=7). In \( \binom{n}{a}=\binom{n}{b} \), often (a+b=n) is useful.

Step 2

Why this answer is correct

The correct answer is B. (7). By symmetry, (r+(r-3)=11), so (r=7). In \( \binom{n}{a}=\binom{n}{b} \), often (a+b=n) is useful.

Step 3

Exam Tip

सममिति से (r+(r-3)=11), इसलिए (r=7) है। \( \binom{n}{a}=\binom{n}{b} \) में अक्सर (a+b=n) काम आता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \( \binom{11}{r}=\binom{11}{r-3} \), तो ( r ) का मान क्या है? / If \( \binom{11}{r}=\binom{11}{r-3} \), what is the value of ( r )?

Correct Answer: B. (7). Explanation: सममिति से (r+(r-3)=11), इसलिए (r=7) है। \( \binom{n}{a}=\binom{n}{b} \) में अक्सर (a+b=n) काम आता है। / By symmetry, (r+(r-3)=11), so (r=7). In \( \binom{n}{a}=\binom{n}{b} \), often (a+b=n) is useful.

Which concept should I revise for this Mathematics MCQ?

By symmetry, (r+(r-3)=11), so (r=7). In \( \binom{n}{a}=\binom{n}{b} \), often (a+b=n) is useful.

What exam hint can help solve this Mathematics question?

सममिति से (r+(r-3)=11), इसलिए (r=7) है। \( \binom{n}{a}=\binom{n}{b} \) में अक्सर (a+b=n) काम आता है।