यदि \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) और \(B={x:x\in\mathbb{Z},;x^2<10}\), तो \(A\setminus B\) क्या है?
If \(A={x:x\in\mathbb{Z},;-3\le x\le 4}\) and \(B={x:x\in\mathbb{Z},;x^2<10}\), what is \(A\setminus B\)?
Explanation opens after your attempt
A. ({4})
Concept
Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.
Why this answer is correct
The correct answer is A. ({4}). Here \(B=\{-3,-2,-1,0,1,2,3\}\), and only (4) remains extra in (A). Build each set first, then take the difference.
Exam Tip
\(B=\{-3,-2,-1,0,1,2,3\}\) है और (A) में अतिरिक्त केवल (4) है। असमानता से सेट बनाकर फिर अंतर लें।
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