यदि \(A={x:x\in\mathbb{R},\ x^2<9}\) और \(B={x:x\in\mathbb{R},\ x\ge1}\), तो \(A\cap B\) क्या है?
If \(A={x:x\in\mathbb{R},\ x^2<9}\) and \(B={x:x\in\mathbb{R},\ x\ge1}\), what is \(A\cap B\)?
Explanation opens after your attempt
Correct Answer
A. ([1,3))
Concept
\(x^2<9\) gives (-3<x<3), and combining with \(x\ge1\) gives ([1,3)). Check endpoints carefully in inequalities.
Why this answer is correct
The correct answer is A. ([1,3)). \(x^2<9\) gives (-3<x<3), and combining with \(x\ge1\) gives ([1,3)). Check endpoints carefully in inequalities.
Exam Tip
\(x^2<9\) से (-3<x<3) और \(x\ge1\) मिलाकर ([1,3)) मिलता है। असमानताओं में सिरों की जांच करें।
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