यदि \(A={x:x\in\mathbb{N},;x\le 25,;x is odd}\) और (B={x:x\in\mathbb{N},;x\le 25,;\(3\mid x}), तो (|A\cap B|) कितना है\)?

If \(A={x:x\in\mathbb{N},;x\le 25,;x is odd}\) and (B={x:x\in\mathbb{N},;x\le 25,;\(3\mid x}), what is (|A\cap B|)\)?

Explanation opens after your attempt
Correct Answer

A. (5)

Step 1

Concept

Multiples of (3) up to (25) are (3,6,9,12,15,18,21,24). The odd ones are (3,9,15,21), so the count is (4).

Step 2

Why this answer is correct

The correct answer is A. (5). Multiples of (3) up to (25) are (3,6,9,12,15,18,21,24). The odd ones are (3,9,15,21), so the count is (4).

Step 3

Exam Tip

(25) तक (3) के गुणज (3,6,9,12,15,18,21,24) हैं। इनमें विषम (3,9,15,21,25) नहीं, बल्कि (3,9,15,21) और (?) नहीं; कुल (4) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{N},;x\le 25,;x is odd}\) और \(B={x:x\in\mathbb{N},;x\le 25,;3\mid x}\), तो \(|A\cap B|\) कितना है? / If \(A={x:x\in\mathbb{N},;x\le 25,;x is odd}\) and (B={x:x\in\mathbb{N},;x\le 25,;\(3\mid x}), what is (|A\cap B|)\)?

Correct Answer: A. (5). Explanation: (25) तक (3) के गुणज (3,6,9,12,15,18,21,24) हैं। इनमें विषम (3,9,15,21,25) नहीं, बल्कि (3,9,15,21) और (?) नहीं; कुल (4) है। / Multiples of (3) up to (25) are (3,6,9,12,15,18,21,24). The odd ones are (3,9,15,21), so the count is (4).

Which concept should I revise for this Mathematics MCQ?

Multiples of (3) up to (25) are (3,6,9,12,15,18,21,24). The odd ones are (3,9,15,21), so the count is (4).

What exam hint can help solve this Mathematics question?

(25) तक (3) के गुणज (3,6,9,12,15,18,21,24) हैं। इनमें विषम (3,9,15,21,25) नहीं, बल्कि (3,9,15,21) और (?) नहीं; कुल (4) है।