यदि \(A={x\in\mathbb{Z}: |x|\le 3}\) और \(B={x\in\mathbb{Z}: x^2-2x\le 0}\), तो \(A\cap B\) क्या है?
If \(A={x\in\mathbb{Z}: |x|\le 3}\) and \(B={x\in\mathbb{Z}: x^2-2x\le 0}\), what is \(A\cap B\)?
Explanation opens after your attempt
Correct Answer
A. ({0,1,2})
Concept
\(x^2-2x\le0\) gives \(0\le x\le2\). In integers, \(B=\{0,1,2\}\), which is also in (A).
Why this answer is correct
The correct answer is A. ({0,1,2}). \(x^2-2x\le0\) gives \(0\le x\le2\). In integers, \(B=\{0,1,2\}\), which is also in (A).
Exam Tip
\(x^2-2x\le0\) से \(0\le x\le2\) मिलता है। पूर्णांकों में \(B=\{0,1,2\}\), जो (A) में भी है।
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