यदि \(A={x\in\mathbb{N}:x\le10}\), \(B={x\in\mathbb{N}:x\) विषम है(}) और \(C={x\in\mathbb{N}:x\) अभाज्य है(}), तो \(A\cap(B-C)\) क्या है?
If \(A={x\in\mathbb{N}:x\le10}\), \(B={x\in\mathbb{N}:x\) is odd(}), and \(C={x\in\mathbb{N}:x\) is prime(}), what is \(A\cap(B-C)\)?
Explanation opens after your attempt
Correct Answer
A. ({1,9})
Concept
The odd numbers up to (10) are ({1,3,5,7,9}). Removing primes leaves ({1,9}).
Why this answer is correct
The correct answer is A. ({1,9}). The odd numbers up to (10) are ({1,3,5,7,9}). Removing primes leaves ({1,9}).
Exam Tip
(10) तक की विषम संख्याएं ({1,3,5,7,9}) हैं। इनमें अभाज्य हटाने पर ({1,9}) बचता है।
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