यदि \(A\subseteq B\), (n(A)=38), (n(B)=91) और (n(U)=130) है, तो (n\(B^c\)) कितना होगा?
If \(A\subseteq B\), (n(A)=38), (n(B)=91), and (n(U)=130), what is (n\(B^c\))?
Explanation opens after your attempt
Correct Answer
A. (39)
Concept
\(B^c\) contains elements of (U) not in (B), so (130-91=39). The subset information is not needed here and can be a trap.
Why this answer is correct
The correct answer is A. (39). \(B^c\) contains elements of (U) not in (B), so (130-91=39). The subset information is not needed here and can be a trap.
Exam Tip
\(B^c\) में (U) के वे तत्व हैं जो (B) में नहीं हैं, इसलिए (130-91=39)। उपसमुच्चय जानकारी यहां जरूरी नहीं है, यह जाल हो सकता है।
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