यदि \(A=\{3,6,9,12\}\) और \(B=\{6,12,18,24\}\) है, तो \((A-B)\cap(B-A)\) क्या है?

If \(A=\{3,6,9,12\}\) and \(B=\{6,12,18,24\}\), what is \((A-B)\cap(B-A)\)?

Explanation opens after your attempt
Correct Answer

C. \( \varnothing \)

Step 1

Concept

(A-B={3,9}) and (B-A={18,24}), and they have no common element. Therefore their intersection is \(\varnothing\).

Step 2

Why this answer is correct

The correct answer is C. \( \varnothing \). (A-B={3,9}) and (B-A={18,24}), and they have no common element. Therefore their intersection is \(\varnothing\).

Step 3

Exam Tip

(A-B={3,9}) और (B-A={18,24}) हैं, जिनमें कोई समान अवयव नहीं है। इसलिए उनका प्रतिच्छेद \(\varnothing\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{3,6,9,12\}\) और \(B=\{6,12,18,24\}\) है, तो \((A-B)\cap(B-A)\) क्या है? / If \(A=\{3,6,9,12\}\) and \(B=\{6,12,18,24\}\), what is \((A-B)\cap(B-A)\)?

Correct Answer: C. \( \varnothing \). Explanation: (A-B={3,9}) और (B-A={18,24}) हैं, जिनमें कोई समान अवयव नहीं है। इसलिए उनका प्रतिच्छेद \(\varnothing\) है। / (A-B={3,9}) and (B-A={18,24}), and they have no common element. Therefore their intersection is \(\varnothing\).

Which concept should I revise for this Mathematics MCQ?

(A-B={3,9}) and (B-A={18,24}), and they have no common element. Therefore their intersection is \(\varnothing\).

What exam hint can help solve this Mathematics question?

(A-B={3,9}) और (B-A={18,24}) हैं, जिनमें कोई समान अवयव नहीं है। इसलिए उनका प्रतिच्छेद \(\varnothing\) है।