यदि (10)-letter word में (A) (4) बार और (B) (2) बार है, तो arrangements का divisor क्या होगा?
If a (10)-letter word has (A) (4) times and (B) (2) times, what will be the divisor for arrangements?
Explanation opens after your attempt
A. (4!2!)
Concept
Internal interchanges of repeated letters do not create new arrangements. In exams divide by the factorial of each repeated group.
Why this answer is correct
The correct answer is A. (4!2!). Internal interchanges of repeated letters do not create new arrangements. In exams divide by the factorial of each repeated group.
Exam Tip
Repeated letters की अंदरूनी अदला-बदली नई arrangement नहीं बनाती। परीक्षा में हर repeated group के factorial से भाग दें।
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