यदि \(A=\{1,2\}\), \(B=\{3\}\) और \(C=\{4,5\}\) हैं, तो (n\(A\times B\times C\)) कितना होगा?

If \(A=\{1,2\}\), \(B=\{3\}\), and \(C=\{4,5\}\), what is (n\(A\times B\times C\))?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

For the product of three sets, the count is (n(A)n(B)n(C)), so \(2\times 1\times 2=4\). This counts ordered triples.

Step 2

Why this answer is correct

The correct answer is B. (4). For the product of three sets, the count is (n(A)n(B)n(C)), so \(2\times 1\times 2=4\). This counts ordered triples.

Step 3

Exam Tip

तीन समुच्चयों के गुणन में संख्या (n(A)n(B)n(C)) होती है, इसलिए \(2\times 1\times 2=4\)। यह क्रमित त्रिकों की गिनती है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2\}\), \(B=\{3\}\) और \(C=\{4,5\}\) हैं, तो (n\(A\times B\times C\)) कितना होगा? / If \(A=\{1,2\}\), \(B=\{3\}\), and \(C=\{4,5\}\), what is (n\(A\times B\times C\))?

Correct Answer: B. (4). Explanation: तीन समुच्चयों के गुणन में संख्या (n(A)n(B)n(C)) होती है, इसलिए \(2\times 1\times 2=4\)। यह क्रमित त्रिकों की गिनती है। / For the product of three sets, the count is (n(A)n(B)n(C)), so \(2\times 1\times 2=4\). This counts ordered triples.

Which concept should I revise for this Mathematics MCQ?

For the product of three sets, the count is (n(A)n(B)n(C)), so \(2\times 1\times 2=4\). This counts ordered triples.

What exam hint can help solve this Mathematics question?

तीन समुच्चयों के गुणन में संख्या (n(A)n(B)n(C)) होती है, इसलिए \(2\times 1\times 2=4\)। यह क्रमित त्रिकों की गिनती है।