यदि \(A=\{1,2,3\}\) और \(B=\{1,2,3,4,5,6\}\) हैं, तो \(A\times B\) में कितने युग्म ((a,b)) ऐसे हैं जिनमें (b) (a) का गुणज है पर \(b\ne a\) है?

If \(A=\{1,2,3\}\) and \(B=\{1,2,3,4,5,6\}\), how many pairs ((a,b)) in \(A\times B\) have (b) as a multiple of (a) but \(b\ne a\)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

The total multiple count is (6+3+2=11), and ((1,1),(2,2),(3,3)) are removed. Thus (11-3=8).

Step 2

Why this answer is correct

The correct answer is A. (8). The total multiple count is (6+3+2=11), and ((1,1),(2,2),(3,3)) are removed. Thus (11-3=8).

Step 3

Exam Tip

गुणजों की कुल गिनती (6+3+2=11) है और ((1,1),(2,2),(3,3)) हटते हैं। इसलिए (11-3=8)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3\}\) और \(B=\{1,2,3,4,5,6\}\) हैं, तो \(A\times B\) में कितने युग्म ((a,b)) ऐसे हैं जिनमें (b) (a) का गुणज है पर \(b\ne a\) है? / If \(A=\{1,2,3\}\) and \(B=\{1,2,3,4,5,6\}\), how many pairs ((a,b)) in \(A\times B\) have (b) as a multiple of (a) but \(b\ne a\)?

Correct Answer: A. (8). Explanation: गुणजों की कुल गिनती (6+3+2=11) है और ((1,1),(2,2),(3,3)) हटते हैं। इसलिए (11-3=8)। / The total multiple count is (6+3+2=11), and ((1,1),(2,2),(3,3)) are removed. Thus (11-3=8).

Which concept should I revise for this Mathematics MCQ?

The total multiple count is (6+3+2=11), and ((1,1),(2,2),(3,3)) are removed. Thus (11-3=8).

What exam hint can help solve this Mathematics question?

गुणजों की कुल गिनती (6+3+2=11) है और ((1,1),(2,2),(3,3)) हटते हैं। इसलिए (11-3=8)।