यदि \(A=\{1,2,3,4\}\) और \(R=\{(x,y):y=x+1\}\) हो तो (R) में कौन सा युग्म नहीं आएगा?

If \(A=\{1,2,3,4\}\) and \(R=\{(x,y):y=x+1\}\), which pair will not appear in (R)?

Explanation opens after your attempt
Correct Answer

D. \((4,5)\)

Step 1

Concept

In ((4,5)), \(5\notin A\), so it is not a pair of \(A\times A\). While forming a relation, both components must belong to the set.

Step 2

Why this answer is correct

The correct answer is D. \((4,5)\). In ((4,5)), \(5\notin A\), so it is not a pair of \(A\times A\). While forming a relation, both components must belong to the set.

Step 3

Exam Tip

((4,5)) में \(5\notin A\) है इसलिए यह \(A\times A\) का युग्म नहीं है। संबंध बनाते समय दोनों अवयव समुच्चय में होने चाहिए।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4\}\) और \(R=\{(x,y):y=x+1\}\) हो तो (R) में कौन सा युग्म नहीं आएगा? / If \(A=\{1,2,3,4\}\) and \(R=\{(x,y):y=x+1\}\), which pair will not appear in (R)?

Correct Answer: D. \((4,5)\). Explanation: ((4,5)) में \(5\notin A\) है इसलिए यह \(A\times A\) का युग्म नहीं है। संबंध बनाते समय दोनों अवयव समुच्चय में होने चाहिए। / In ((4,5)), \(5\notin A\), so it is not a pair of \(A\times A\). While forming a relation, both components must belong to the set.

Which concept should I revise for this Mathematics MCQ?

In ((4,5)), \(5\notin A\), so it is not a pair of \(A\times A\). While forming a relation, both components must belong to the set.

What exam hint can help solve this Mathematics question?

((4,5)) में \(5\notin A\) है इसलिए यह \(A\times A\) का युग्म नहीं है। संबंध बनाते समय दोनों अवयव समुच्चय में होने चाहिए।