यदि \(A=\{1,2,3,4,5,6\}\) है, तो (\mathcal{P}(A)) में ठीक (4) तत्व वाले समुच्चयों की संख्या कितनी है?

If \(A=\{1,2,3,4,5,6\}\), how many sets in (\mathcal{P}(A)) have exactly (4) elements?

Explanation opens after your attempt
Correct Answer

B. (15)

Step 1

Concept

The number of ways to choose exactly (4) elements is \(\binom{6}{4}=15\). Every such subset is counted in the power set.

Step 2

Why this answer is correct

The correct answer is B. (15). The number of ways to choose exactly (4) elements is \(\binom{6}{4}=15\). Every such subset is counted in the power set.

Step 3

Exam Tip

ठीक (4) तत्व चुनने की संख्या \(\binom{6}{4}=15\) है। ऐसे हर उपसमुच्चय को घात समुच्चय में गिना जाता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4,5,6\}\) है, तो (\mathcal{P}(A)) में ठीक (4) तत्व वाले समुच्चयों की संख्या कितनी है? / If \(A=\{1,2,3,4,5,6\}\), how many sets in (\mathcal{P}(A)) have exactly (4) elements?

Correct Answer: B. (15). Explanation: ठीक (4) तत्व चुनने की संख्या \(\binom{6}{4}=15\) है। ऐसे हर उपसमुच्चय को घात समुच्चय में गिना जाता है। / The number of ways to choose exactly (4) elements is \(\binom{6}{4}=15\). Every such subset is counted in the power set.

Which concept should I revise for this Mathematics MCQ?

The number of ways to choose exactly (4) elements is \(\binom{6}{4}=15\). Every such subset is counted in the power set.

What exam hint can help solve this Mathematics question?

ठीक (4) तत्व चुनने की संख्या \(\binom{6}{4}=15\) है। ऐसे हर उपसमुच्चय को घात समुच्चय में गिना जाता है।