यदि \(2x+y\le14\), \(x+2y\le14\), \(x\ge0\), \(y\ge0\) हैं, तो हल क्षेत्र का वह शीर्ष कौन सा है जहां दोनों तिरछी रेखाएं मिलती हैं?
If \(2x+y\le14\), \(x+2y\le14\), \(x\ge0\), \(y\ge0\), which vertex is where the two slant lines meet?
Explanation opens after your attempt
Correct Answer
C. ( \left\(\frac{14}{3},\frac{14}{3}\right\) )
Concept
The two equations give (x=y) and (3x=14), so the vertex is ( \left\(\frac{14}{3},\frac{14}{3}\right\) ). Symmetric boundaries can quickly give (x=y).
Why this answer is correct
The correct answer is C. ( \left\(\frac{14}{3},\frac{14}{3}\right\) ). The two equations give (x=y) and (3x=14), so the vertex is ( \left\(\frac{14}{3},\frac{14}{3}\right\) ). Symmetric boundaries can quickly give (x=y).
Exam Tip
दोनों समीकरणों से (x=y) और (3x=14), इसलिए शीर्ष ( \left\(\frac{14}{3},\frac{14}{3}\right\) ) है। सममित सीमाओं में (x=y) जल्दी मिल सकता है।
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