Class 11 Mathematics Permutations and Combinations Derivations of formulas and their connections Easy Level 66

(4) अलग अक्षरों से repetition allowed होने पर (3)-letter codes की संख्या क्या होगी?

How many (3)-letter codes can be made from (4) distinct letters when repetition is allowed?

Explanation opens after your attempt
Correct Answer

C. \(4^3\)

Step 1

Concept

Each position has (4) choices again and again. In exams use the power formula \(n^r\) when repetition is allowed.

Step 2

Why this answer is correct

The correct answer is C. \(4^3\). Each position has (4) choices again and again. In exams use the power formula \(n^r\) when repetition is allowed.

Step 3

Exam Tip

हर स्थान पर (4) विकल्प बार-बार उपलब्ध हैं। परीक्षा में repetition allowed हो तो power formula \(n^r\) लगाएँ।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

Check out these related questions:

  1. यदि \(\theta\) चतुर्थ चतुर्थांश में है और \(\cos \theta=\frac{8}{17}\), तो \(\tan \theta\) क्या होगा?
  2. यदि \(\sin x+\sin^2 x=0\), तो \(0\leq x<2\pi\) में कितने हल हैं?
  3. फलन (f(x)=\sin 2x+\sin 4x) का मूल आवर्त क्या है?
  4. \(5\sin x-12\cos x\) का अधिकतम मान क्या है?
  5. यदि \(\cos x=-\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  6. यदि \(\sin x=\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  7. \(\cos 3x\) का सही विस्तार कौन-सा है?
  8. \(\sin 3x\) का सही विस्तार कौन-सा है?
  9. यदि (x) तृतीय चतुर्थांश में है और \(\tan x=\frac{4}{3}\), तो \(\sin x\) क्या है?
  10. यदि (x) द्वितीय चतुर्थांश में है और \(\sin x=\frac{5}{13}\), तो \(\cos x\) क्या होगा?

Related Mathematics Learning Links

Mathematics Subject

Level-wise subject practice

Permutations and Combinations Quiz

Chapter-wise MCQ practice

Search Similar MCQs

Find related questions

Daily Challenge

Fresh quiz practice
FAQs

Mathematics Answer, Explanation and Revision Hints

(4) अलग अक्षरों से repetition allowed होने पर (3)-letter codes की संख्या क्या होगी? / How many (3)-letter codes can be made from (4) distinct letters when repetition is allowed?

Correct Answer: C. \(4^3\). Explanation: हर स्थान पर (4) विकल्प बार-बार उपलब्ध हैं। परीक्षा में repetition allowed हो तो power formula \(n^r\) लगाएँ। / Each position has (4) choices again and again. In exams use the power formula \(n^r\) when repetition is allowed.

Which concept should I revise for this Mathematics MCQ?

Each position has (4) choices again and again. In exams use the power formula \(n^r\) when repetition is allowed.

What exam hint can help solve this Mathematics question?

हर स्थान पर (4) विकल्प बार-बार उपलब्ध हैं। परीक्षा में repetition allowed हो तो power formula \(n^r\) लगाएँ।