Class 11 Mathematics Permutations and Combinations Combinations Medium Level 61

(9) विद्यार्थियों में से (4) की टीम बनानी है जिसमें (2) विशेष विद्यार्थी दोनों शामिल हों या दोनों न हों। कितने तरीके हैं?

From (9) students a team of (4) is to be formed in which (2) special students are either both included or both excluded. How many ways are there?

Explanation opens after your attempt
Correct Answer

C. (70)

Step 1

Concept

If both are included there are \(\binom{7}{2}=21\) ways and if both are excluded there are \(\binom{7}{4}=35\) ways. The total is (56).

Step 2

Why this answer is correct

The correct answer is C. (70). If both are included there are \(\binom{7}{2}=21\) ways and if both are excluded there are \(\binom{7}{4}=35\) ways. The total is (56).

Step 3

Exam Tip

दोनों शामिल हों तो \(\binom{7}{2}=21\) और दोनों बाहर हों तो \(\binom{7}{4}=35\) तरीके हैं। कुल (21+35=56) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

Check out these related questions:

  1. यदि \(\theta\) चतुर्थ चतुर्थांश में है और \(\cos \theta=\frac{8}{17}\), तो \(\tan \theta\) क्या होगा?
  2. यदि \(\sin x+\sin^2 x=0\), तो \(0\leq x<2\pi\) में कितने हल हैं?
  3. फलन (f(x)=\sin 2x+\sin 4x) का मूल आवर्त क्या है?
  4. \(5\sin x-12\cos x\) का अधिकतम मान क्या है?
  5. यदि \(\cos x=-\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  6. यदि \(\sin x=\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  7. \(\cos 3x\) का सही विस्तार कौन-सा है?
  8. \(\sin 3x\) का सही विस्तार कौन-सा है?
  9. यदि (x) तृतीय चतुर्थांश में है और \(\tan x=\frac{4}{3}\), तो \(\sin x\) क्या है?
  10. यदि (x) द्वितीय चतुर्थांश में है और \(\sin x=\frac{5}{13}\), तो \(\cos x\) क्या होगा?

Related Mathematics Learning Links

Mathematics Subject

Level-wise subject practice

Permutations and Combinations Quiz

Chapter-wise MCQ practice

Search Similar MCQs

Find related questions

Daily Challenge

Fresh quiz practice
FAQs

Mathematics Answer, Explanation and Revision Hints

(9) विद्यार्थियों में से (4) की टीम बनानी है जिसमें (2) विशेष विद्यार्थी दोनों शामिल हों या दोनों न हों। कितने तरीके हैं? / From (9) students a team of (4) is to be formed in which (2) special students are either both included or both excluded. How many ways are there?

Correct Answer: C. (70). Explanation: दोनों शामिल हों तो \(\binom{7}{2}=21\) और दोनों बाहर हों तो \(\binom{7}{4}=35\) तरीके हैं। कुल (21+35=56) है। / If both are included there are \(\binom{7}{2}=21\) ways and if both are excluded there are \(\binom{7}{4}=35\) ways. The total is (56).

Which concept should I revise for this Mathematics MCQ?

If both are included there are \(\binom{7}{2}=21\) ways and if both are excluded there are \(\binom{7}{4}=35\) ways. The total is (56).

What exam hint can help solve this Mathematics question?

दोनों शामिल हों तो \(\binom{7}{2}=21\) और दोनों बाहर हों तो \(\binom{7}{4}=35\) तरीके हैं। कुल (21+35=56) है।