(15) पुस्तकों में से (6) पुस्तकें चुननी हैं जिनमें दो विशेष पुस्तकें दोनों साथ न आएं। कितने तरीके हैं?

From (15) books (6) books are to be selected so that two special books do not appear together. How many ways are there?

Explanation opens after your attempt
Correct Answer

A. (4290)

Step 1

Concept

Total ways are \(\binom{15}{6}=5005\) and ways with both special books are \(\binom{13}{4}=715\). Hence (5005-715=4290).

Step 2

Why this answer is correct

The correct answer is A. (4290). Total ways are \(\binom{15}{6}=5005\) and ways with both special books are \(\binom{13}{4}=715\). Hence (5005-715=4290).

Step 3

Exam Tip

कुल \(\binom{15}{6}=5005\) हैं और दोनों विशेष साथ हों तो \(\binom{13}{4}=715\) हैं। इसलिए (5005-715=4290) तरीके हैं।

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(15) पुस्तकों में से (6) पुस्तकें चुननी हैं जिनमें दो विशेष पुस्तकें दोनों साथ न आएं। कितने तरीके हैं? / From (15) books (6) books are to be selected so that two special books do not appear together. How many ways are there?

Correct Answer: A. (4290). Explanation: कुल \(\binom{15}{6}=5005\) हैं और दोनों विशेष साथ हों तो \(\binom{13}{4}=715\) हैं। इसलिए (5005-715=4290) तरीके हैं। / Total ways are \(\binom{15}{6}=5005\) and ways with both special books are \(\binom{13}{4}=715\). Hence (5005-715=4290).

Which concept should I revise for this Mathematics MCQ?

Total ways are \(\binom{15}{6}=5005\) and ways with both special books are \(\binom{13}{4}=715\). Hence (5005-715=4290).

What exam hint can help solve this Mathematics question?

कुल \(\binom{15}{6}=5005\) हैं और दोनों विशेष साथ हों तो \(\binom{13}{4}=715\) हैं। इसलिए (5005-715=4290) तरीके हैं।