(14) विद्यार्थियों में से (6) चुनने हैं। (4) विशेष विद्यार्थियों में से ठीक (2) या ठीक (3) शामिल हों। कितने तरीके हैं?
From (14) students (6) are to be selected. Exactly (2) or exactly (3) of (4) special students must be included. How many ways are there?
Explanation opens after your attempt
Correct Answer
C. (2100)
Concept
The cases are (2) special and (3) special students. The total is \(\binom{4}{2}\binom{10}{4}+\binom{4}{3}\binom{10}{3}=2100\).
Why this answer is correct
The correct answer is C. (2100). The cases are (2) special and (3) special students. The total is \(\binom{4}{2}\binom{10}{4}+\binom{4}{3}\binom{10}{3}=2100\).
Exam Tip
मामले (2) विशेष और (3) विशेष के हैं। कुल \(\binom{4}{2}\binom{10}{4}+\binom{4}{3}\binom{10}{3}=2100\) है।
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