असमीका (5(2-x)\ge 3(4+x)+1) का समाधान समुच्चय चुनिए।

Choose the solution set of (5(2-x)\ge 3(4+x)+1).

Explanation opens after your attempt
Correct Answer

C. \(x\le -\frac{3}{8}\)

Step 1

Concept

\(10-5x\ge 13+3x\) gives \(-8x\ge 3\), so \(x\le -\frac{3}{8}\). Reverse the sign when dividing by a negative coefficient.

Step 2

Why this answer is correct

The correct answer is C. \(x\le -\frac{3}{8}\). \(10-5x\ge 13+3x\) gives \(-8x\ge 3\), so \(x\le -\frac{3}{8}\). Reverse the sign when dividing by a negative coefficient.

Step 3

Exam Tip

\(10-5x\ge 13+3x\) से \(-8x\ge 3\), इसलिए \(x\le -\frac{3}{8}\)। परीक्षा में ऋणात्मक गुणांक से भाग देने पर चिन्ह पलटें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमीका (5(2-x)\ge 3(4+x)+1) का समाधान समुच्चय चुनिए। / Choose the solution set of (5(2-x)\ge 3(4+x)+1).

Correct Answer: C. \(x\le -\frac{3}{8}\). Explanation: \(10-5x\ge 13+3x\) से \(-8x\ge 3\), इसलिए \(x\le -\frac{3}{8}\)। परीक्षा में ऋणात्मक गुणांक से भाग देने पर चिन्ह पलटें। / \(10-5x\ge 13+3x\) gives \(-8x\ge 3\), so \(x\le -\frac{3}{8}\). Reverse the sign when dividing by a negative coefficient.

Which concept should I revise for this Mathematics MCQ?

\(10-5x\ge 13+3x\) gives \(-8x\ge 3\), so \(x\le -\frac{3}{8}\). Reverse the sign when dividing by a negative coefficient.

What exam hint can help solve this Mathematics question?

\(10-5x\ge 13+3x\) से \(-8x\ge 3\), इसलिए \(x\le -\frac{3}{8}\)। परीक्षा में ऋणात्मक गुणांक से भाग देने पर चिन्ह पलटें।