असमानता \(-6+\frac{5x}{2}\le \frac{x-3}{4}\) का हल चुनिए।

Choose the solution of \(-6+\frac{5x}{2}\le \frac{x-3}{4}\).

Explanation opens after your attempt
Correct Answer

A. \(x\le \frac{21}{9}\)

Step 1

Concept

Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).

Step 2

Why this answer is correct

The correct answer is A. \(x\le \frac{21}{9}\). Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).

Step 3

Exam Tip

(4) से गुणा करने पर \(-24+10x\le x-3\) मिलता है। इससे \(9x\le 21\), अतः \(x\le \frac{7}{3}\)।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(-6+\frac{5x}{2}\le \frac{x-3}{4}\) का हल चुनिए। / Choose the solution of \(-6+\frac{5x}{2}\le \frac{x-3}{4}\).

Correct Answer: A. \(x\le \frac{21}{9}\). Explanation: (4) से गुणा करने पर \(-24+10x\le x-3\) मिलता है। इससे \(9x\le 21\), अतः \(x\le \frac{7}{3}\)। / Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).

What exam hint can help solve this Mathematics question?

(4) से गुणा करने पर \(-24+10x\le x-3\) मिलता है। इससे \(9x\le 21\), अतः \(x\le \frac{7}{3}\)।