असमानता \(-6+\frac{5x}{2}\le \frac{x-3}{4}\) का हल चुनिए।
Choose the solution of \(-6+\frac{5x}{2}\le \frac{x-3}{4}\).
Explanation opens after your attempt
A. \(x\le \frac{21}{9}\)
Concept
Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).
Why this answer is correct
The correct answer is A. \(x\le \frac{21}{9}\). Multiplying by (4) gives \(-24+10x\le x-3\). Thus \(9x\le 21\), so \(x\le \frac{7}{3}\).
Exam Tip
(4) से गुणा करने पर \(-24+10x\le x-3\) मिलता है। इससे \(9x\le 21\), अतः \(x\le \frac{7}{3}\)।
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