फलन (f(x)=\sqrt{9-(x-1)2}) का परिसर चुनिए।
Choose the range of (f(x)=\sqrt{9-(x-1)2}).
Explanation opens after your attempt
A. ([0,3])
Concept
A square root is never negative and the maximum inside value is (9). Hence the range is ([0,3]).
Why this answer is correct
The correct answer is A. ([0,3]). A square root is never negative and the maximum inside value is (9). Hence the range is ([0,3]).
Exam Tip
वर्गमूल का मान ऋणात्मक नहीं होता और अंदर का अधिकतम मान (9) है। इसलिए परिसर ([0,3]) है।
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