फलन (f(x)=\sqrt{2x-x-2}) का परिसर चुनिए।
Choose the range of (f(x)=\sqrt{2x-x-2}).
Explanation opens after your attempt
A. ([0,1])
Concept
(2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).
Why this answer is correct
The correct answer is A. ([0,1]). (2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).
Exam Tip
(2x-x-2=1-(x-1)2), जिसका अधिकतम मान (1) है। वर्गमूल से परिसर ([0,1]) मिलता है।
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