फलन (f(x)=\sqrt{2x-x-2}) का परिसर चुनिए।

Choose the range of (f(x)=\sqrt{2x-x-2}).

Explanation opens after your attempt
Correct Answer

A. ([0,1])

Step 1

Concept

(2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).

Step 2

Why this answer is correct

The correct answer is A. ([0,1]). (2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).

Step 3

Exam Tip

(2x-x-2=1-(x-1)2), जिसका अधिकतम मान (1) है। वर्गमूल से परिसर ([0,1]) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{2x-x-2}) का परिसर चुनिए। / Choose the range of (f(x)=\sqrt{2x-x-2}).

Correct Answer: A. ([0,1]). Explanation: (2x-x-2=1-(x-1)2), जिसका अधिकतम मान (1) है। वर्गमूल से परिसर ([0,1]) मिलता है। / (2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).

Which concept should I revise for this Mathematics MCQ?

(2x-x-2=1-(x-1)2), whose maximum value is (1). The square root gives the range ([0,1]).

What exam hint can help solve this Mathematics question?

(2x-x-2=1-(x-1)2), जिसका अधिकतम मान (1) है। वर्गमूल से परिसर ([0,1]) मिलता है।