ग्राफ \(y=x^2+2x-8\) (x)-अक्ष को किन (x) मानों पर काटता है?

At which (x) values does \(y=x^2+2x-8\) cut the (x)-axis?

Explanation opens after your attempt
Correct Answer

A. (x=-4,2)

Step 1

Concept

Set (y=0) on the (x)-axis. From \(x^2+2x-8=0\), (x=-4,2).

Step 2

Why this answer is correct

The correct answer is A. (x=-4,2). Set (y=0) on the (x)-axis. From \(x^2+2x-8=0\), (x=-4,2).

Step 3

Exam Tip

(x)-अक्ष पर (y=0) रखें। \(x^2+2x-8=0\) से (x=-4,2) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=x^2+2x-8\) (x)-अक्ष को किन (x) मानों पर काटता है? / At which (x) values does \(y=x^2+2x-8\) cut the (x)-axis?

Correct Answer: A. (x=-4,2). Explanation: (x)-अक्ष पर (y=0) रखें। \(x^2+2x-8=0\) से (x=-4,2) मिलता है। / Set (y=0) on the (x)-axis. From \(x^2+2x-8=0\), (x=-4,2).

Which concept should I revise for this Mathematics MCQ?

Set (y=0) on the (x)-axis. From \(x^2+2x-8=0\), (x=-4,2).

What exam hint can help solve this Mathematics question?

(x)-अक्ष पर (y=0) रखें। \(x^2+2x-8=0\) से (x=-4,2) मिलता है।