फलन \(y=|x^2-1|\) (x)-अक्ष को किन बिंदुओं पर काटता है?
At which points does \(y=|x^2-1|\) cut the (x)-axis?
Explanation opens after your attempt
A. ((-1,0)) और ((1,0))((-1,0)) and ((1,0))
Concept
A modulus is zero only when \(x^2-1=0\). This gives \(x=\pm1\).
Why this answer is correct
The correct answer is A. ((-1,0)) और ((1,0)) / ((-1,0)) and ((1,0)). A modulus is zero only when \(x^2-1=0\). This gives \(x=\pm1\).
Exam Tip
मापांक शून्य तभी होता है जब \(x^2-1=0\) हो। इससे \(x=\pm1\) मिलता है।
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