ग्राफ \(y=|x^2-9|\) (x)-अक्ष को किन बिंदुओं पर छूता है?
At which points does the graph \(y=|x^2-9|\) touch the (x)-axis?
Explanation opens after your attempt
A. ((-3,0)) और ((3,0))((-3,0)) and ((3,0))
Concept
\(|x^2-9|=0\) when \(x^2-9=0\), so \(x=\pm3\). In exams, modulus is zero only when the inside expression is zero.
Why this answer is correct
The correct answer is A. ((-3,0)) और ((3,0)) / ((-3,0)) and ((3,0)). \(|x^2-9|=0\) when \(x^2-9=0\), so \(x=\pm3\). In exams, modulus is zero only when the inside expression is zero.
Exam Tip
\(|x^2-9|=0\) तब \(x^2-9=0\) होता है इसलिए \(x=\pm3\)। परीक्षा में मापांक शून्य तभी होता है जब अंदर की राशि शून्य हो।
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