ग्राफ \(y=\frac{2}{x}\) और (y=x) किन बिंदुओं पर मिलते हैं?

At which points do \(y=\frac{2}{x}\) and (y=x) meet?

Explanation opens after your attempt
Correct Answer

A. (\(\sqrt{2},\sqrt{2}\)) और (\(-\sqrt{2},-\sqrt{2}\))(\(\sqrt{2},\sqrt{2}\)) and (\(-\sqrt{2},-\sqrt{2}\))

Step 1

Concept

From \(\frac{2}{x}=x\), we get \(x^2=2\). Hence \(x=\pm\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. (\(\sqrt{2},\sqrt{2}\)) और (\(-\sqrt{2},-\sqrt{2}\)) / (\(\sqrt{2},\sqrt{2}\)) and (\(-\sqrt{2},-\sqrt{2}\)). From \(\frac{2}{x}=x\), we get \(x^2=2\). Hence \(x=\pm\sqrt{2}\).

Step 3

Exam Tip

\(\frac{2}{x}=x\) से \(x^2=2\) मिलता है। इसलिए \(x=\pm\sqrt{2}\) है।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=\frac{2}{x}\) और (y=x) किन बिंदुओं पर मिलते हैं? / At which points do \(y=\frac{2}{x}\) and (y=x) meet?

Correct Answer: A. (\(\sqrt{2},\sqrt{2}\)) और (\(-\sqrt{2},-\sqrt{2}\)) / (\(\sqrt{2},\sqrt{2}\)) and (\(-\sqrt{2},-\sqrt{2}\)). Explanation: \(\frac{2}{x}=x\) से \(x^2=2\) मिलता है। इसलिए \(x=\pm\sqrt{2}\) है। / From \(\frac{2}{x}=x\), we get \(x^2=2\). Hence \(x=\pm\sqrt{2}\).

Which concept should I revise for this Mathematics MCQ?

From \(\frac{2}{x}=x\), we get \(x^2=2\). Hence \(x=\pm\sqrt{2}\).

What exam hint can help solve this Mathematics question?

\(\frac{2}{x}=x\) से \(x^2=2\) मिलता है। इसलिए \(x=\pm\sqrt{2}\) है।