ग्राफ \(y=\frac{1}{x}\) और (y=x) किन बिंदुओं पर मिलते हैं?

At which points do the graphs \(y=\frac{1}{x}\) and (y=x) meet?

Explanation opens after your attempt
Correct Answer

A. ((1,1)) और ((-1,-1))((1,1)) and ((-1,-1))

Step 1

Concept

From \(\frac{1}{x}=x\), we get \(x^2=1\). Hence \(x=\pm1\) and the points are ((1,1)), ((-1,-1)).

Step 2

Why this answer is correct

The correct answer is A. ((1,1)) और ((-1,-1)) / ((1,1)) and ((-1,-1)). From \(\frac{1}{x}=x\), we get \(x^2=1\). Hence \(x=\pm1\) and the points are ((1,1)), ((-1,-1)).

Step 3

Exam Tip

\(\frac{1}{x}=x\) से \(x^2=1\) मिलता है। इसलिए \(x=\pm1\) और बिंदु ((1,1)), ((-1,-1)) हैं।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=\frac{1}{x}\) और (y=x) किन बिंदुओं पर मिलते हैं? / At which points do the graphs \(y=\frac{1}{x}\) and (y=x) meet?

Correct Answer: A. ((1,1)) और ((-1,-1)) / ((1,1)) and ((-1,-1)). Explanation: \(\frac{1}{x}=x\) से \(x^2=1\) मिलता है। इसलिए \(x=\pm1\) और बिंदु ((1,1)), ((-1,-1)) हैं। / From \(\frac{1}{x}=x\), we get \(x^2=1\). Hence \(x=\pm1\) and the points are ((1,1)), ((-1,-1)).

Which concept should I revise for this Mathematics MCQ?

From \(\frac{1}{x}=x\), we get \(x^2=1\). Hence \(x=\pm1\) and the points are ((1,1)), ((-1,-1)).

What exam hint can help solve this Mathematics question?

\(\frac{1}{x}=x\) से \(x^2=1\) मिलता है। इसलिए \(x=\pm1\) और बिंदु ((1,1)), ((-1,-1)) हैं।