ग्राफ \(y=x^3+2\) (y)-अक्ष को किस बिंदु पर काटता है?
At which point does the graph \(y=x^3+2\) cut the (y)-axis?
Explanation opens after your attempt
Correct Answer
A. ((0,2))
Concept
On the (y)-axis, set (x=0). Then \(y=0^3+2=2\).
Why this answer is correct
The correct answer is A. ((0,2)). On the (y)-axis, set (x=0). Then \(y=0^3+2=2\).
Exam Tip
(y)-अक्ष पर (x=0) रखें। तब \(y=0^3+2=2\) मिलता है।
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