(8) अलग-अलग मोतियों की माला बनानी है। यदि दो विशेष मोती साथ रहें और पलटना समान माना जाए, तो कितनी मालाएं बनेंगी?
A necklace is to be made with (8) distinct beads. If two particular beads remain together and flipping is considered the same, how many necklaces are possible?
Explanation opens after your attempt
Correct Answer
A. (720)
Concept
Treat the two beads as one block, so the necklace count for (7) units is (\frac{(7-1)!}{2}), with (2!) internal ways. The total is (720).
Why this answer is correct
The correct answer is A. (720). Treat the two beads as one block, so the necklace count for (7) units is (\frac{(7-1)!}{2}), with (2!) internal ways. The total is (720).
Exam Tip
दो मोतियों को एक ब्लॉक मानें, तो (7) इकाइयों की necklace संख्या (\frac{(7-1)!}{2}) है और ब्लॉक के अंदर (2!) तरीके हैं। कुल (720) है।
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