असमानता \(9x-5\ge 4x+20\) का हल क्या है?

What is the solution of the inequality \(9x-5\ge 4x+20\)?

Explanation opens after your attempt
Correct Answer

A. \(x\ge 5\)

Step 1

Concept

Subtracting (4x) and adding (5) gives \(5x\ge 25\), so \(x\ge 5\). Keep the equality part till the end.

Step 2

Why this answer is correct

The correct answer is A. \(x\ge 5\). Subtracting (4x) and adding (5) gives \(5x\ge 25\), so \(x\ge 5\). Keep the equality part till the end.

Step 3

Exam Tip

(4x) घटाने और (5) जोड़ने पर \(5x\ge 25\), इसलिए \(x\ge 5\)। बराबरी का चिह्न अंत में भी रखें।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(9x-5\ge 4x+20\) का हल क्या है? / What is the solution of the inequality \(9x-5\ge 4x+20\)?

Correct Answer: A. \(x\ge 5\). Explanation: (4x) घटाने और (5) जोड़ने पर \(5x\ge 25\), इसलिए \(x\ge 5\)। बराबरी का चिह्न अंत में भी रखें। / Subtracting (4x) and adding (5) gives \(5x\ge 25\), so \(x\ge 5\). Keep the equality part till the end.

Which concept should I revise for this Mathematics MCQ?

Subtracting (4x) and adding (5) gives \(5x\ge 25\), so \(x\ge 5\). Keep the equality part till the end.

What exam hint can help solve this Mathematics question?

(4x) घटाने और (5) जोड़ने पर \(5x\ge 25\), इसलिए \(x\ge 5\)। बराबरी का चिह्न अंत में भी रखें।