यदि (x) वास्तविक है और (x-2<4) तथा \(x+5\geq 1\) है तो संयुक्त हल क्या है?

If (x) is real and (x-2<4) and \(x+5\geq 1\), what is the combined solution?

Explanation opens after your attempt
Correct Answer

A. ([-4,6))

Step 1

Concept

The first inequality gives (x<6), and the second gives \(x\geq -4\). The combined solution is ([-4,6)).

Step 2

Why this answer is correct

The correct answer is A. ([-4,6)). The first inequality gives (x<6), and the second gives \(x\geq -4\). The combined solution is ([-4,6)).

Step 3

Exam Tip

पहली असमता से (x<6) और दूसरी से \(x\geq -4\) मिलता है। संयुक्त हल ([-4,6)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (x) वास्तविक है और (x-2<4) तथा \(x+5\geq 1\) है तो संयुक्त हल क्या है? / If (x) is real and (x-2<4) and \(x+5\geq 1\), what is the combined solution?

Correct Answer: A. ([-4,6)). Explanation: पहली असमता से (x<6) और दूसरी से \(x\geq -4\) मिलता है। संयुक्त हल ([-4,6)) है। / The first inequality gives (x<6), and the second gives \(x\geq -4\). The combined solution is ([-4,6)).

Which concept should I revise for this Mathematics MCQ?

The first inequality gives (x<6), and the second gives \(x\geq -4\). The combined solution is ([-4,6)).

What exam hint can help solve this Mathematics question?

पहली असमता से (x<6) और दूसरी से \(x\geq -4\) मिलता है। संयुक्त हल ([-4,6)) है।