यदि ((k,2)) बिंदु \(2x+y\leq 10\) और (x-y>1) दोनों का हल है, तो (k) की सही सीमा कौन सी है?
If the point ((k,2)) is a solution of both \(2x+y\leq 10\) and (x-y>1), which range of (k) is correct?
Explanation opens after your attempt
B. \(3<k\leq 4\)
Concept
Substitution gives \(2k+2\leq 10\) and (k-2>1). Hence \(k\leq 4\) and (k>3).
Why this answer is correct
The correct answer is B. \(3<k\leq 4\). Substitution gives \(2k+2\leq 10\) and (k-2>1). Hence \(k\leq 4\) and (k>3).
Exam Tip
बिंदु रखने पर \(2k+2\leq 10\) और (k-2>1) मिलता है। इसलिए \(k\leq 4\) और (k>3) होगा।
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