यदि \(\sec x-\tan x=\frac{2}{5}\), तो \(\tan x\) का मान क्या है?
If \(\sec x-\tan x=\frac{2}{5}\), what is the value of \(\tan x\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{21}{20}\)
Concept
Since (\(\sec x-\tan x\)\(\sec x+\tan x\)=1), \(\sec x+\tan x=\frac{5}{2}\). Subtracting the two equations gives \(\tan x=\frac{21}{20}\).
Why this answer is correct
The correct answer is A. \(\frac{21}{20}\). Since (\(\sec x-\tan x\)\(\sec x+\tan x\)=1), \(\sec x+\tan x=\frac{5}{2}\). Subtracting the two equations gives \(\tan x=\frac{21}{20}\).
Exam Tip
क्योंकि (\(\sec x-\tan x\)\(\sec x+\tan x\)=1), इसलिए \(\sec x+\tan x=\frac{5}{2}\)। दोनों समीकरण घटाने पर \(\tan x=\frac{21}{20}\) मिलता है।
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