In pea plants, yellow seed is dominant over green seed. If two heterozygous yellow-seeded plants are crossed, what is the probability of green seeds?
Answer and explanation
Correct answer: One fourth
Let Y represent the dominant yellow allele and y the recessive green allele. Each heterozygous parent is Yy, so the cross is Yy × Yy. The four equally likely combinations are YY, Yy, Yy, and yy. Only yy produces green seeds because the recessive phenotype appears when both alleles are recessive. Thus 1 of 4 outcomes, or 25%, is green. The other three outcomes are yellow, so B, C, and D are incorrect.
Frequently asked questions
What is the correct answer to this question?
One fourth
Why is this the correct answer?
Let Y represent the dominant yellow allele and y the recessive green allele. Each heterozygous parent is Yy, so the cross is Yy × Yy. The four equally likely combinations are YY, Yy, Yy, and yy. Only yy produces green seeds because the recessive phenotype appears when both alleles are recessive. Thus 1 of 4 outcomes, or 25%, is green. The other three outcomes are yellow, so B, C, and D are incorrect.
Which subject and chapter does this question cover?
This is a Class 10 Science question. Chapter: World of Living. Topic: Heredity and Evolution.
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