एक संख्या के वर्ग में (11) घटाने पर (85) मिलता है। धनात्मक संख्या क्या है?

When (11) is subtracted from the square of a number, the result is (85). What is the positive number?

Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{6}\)

Step 1

Concept

Let the number be (x), so \(x^2-11=85\). This gives \(x^2=96\), so the positive number is \(4\sqrt{6}\).

Step 2

Why this answer is correct

The correct answer is A. \(4\sqrt{6}\). Let the number be (x), so \(x^2-11=85\). This gives \(x^2=96\), so the positive number is \(4\sqrt{6}\).

Step 3

Exam Tip

मान लें संख्या (x) है, तो \(x^2-11=85\)। इससे \(x^2=96\), इसलिए धनात्मक संख्या \(4\sqrt{6}\) है।

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एक संख्या के वर्ग में (11) घटाने पर (85) मिलता है। धनात्मक संख्या क्या है? / When (11) is subtracted from the square of a number, the result is (85). What is the positive number?

Correct Answer: A. \(4\sqrt{6}\). Explanation: मान लें संख्या (x) है, तो \(x^2-11=85\)। इससे \(x^2=96\), इसलिए धनात्मक संख्या \(4\sqrt{6}\) है। / Let the number be (x), so \(x^2-11=85\). This gives \(x^2=96\), so the positive number is \(4\sqrt{6}\).

Which concept should I revise for this Mathematics MCQ?

Let the number be (x), so \(x^2-11=85\). This gives \(x^2=96\), so the positive number is \(4\sqrt{6}\).

What exam hint can help solve this Mathematics question?

मान लें संख्या (x) है, तो \(x^2-11=85\)। इससे \(x^2=96\), इसलिए धनात्मक संख्या \(4\sqrt{6}\) है।