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What is the smallest number by which (2^5\times3^2\times7) should be multiplied to make it a perfect cube?
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Answer and explanation
Correct answer: (2\times3\times7^2)
Step 1: In a perfect cube, every prime exponent must be a multiple of (3). Step 2: (2^5) needs one more (2), (3^2) needs one more (3), and (7^1) needs (7^2). Step 3: Complete each exponent to the next multiple of (3).
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What is the correct answer to this question?
(2\times3\times7^2)
Why is this the correct answer?
Step 1: In a perfect cube, every prime exponent must be a multiple of (3). Step 2: (2^5) needs one more (2), (3^2) needs one more (3), and (7^1) needs (7^2). Step 3: Complete each exponent to the next multiple of (3).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Prime Factorisation.
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