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Two workers together complete a work in (6\text{ days}). The first worker alone takes (5\text{ days}) less than the second worker. In how many days will the first worker alone complete the work?

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Answer and explanation

Correct answer: (10\text{ days})

Let the first worker's time be (x\text{ days}), then (\frac{1}{x}+\frac{1}{x+5}=\frac{1}{6}). This gives (x^2-7x-30=0), so (x=10).

Related tags

Quadratic EquationsWork And TimeWord Problems

Frequently asked questions

What is the correct answer to this question?

(10\text{ days})

Why is this the correct answer?

Let the first worker's time be (x\text{ days}), then (\frac{1}{x}+\frac{1}{x+5}=\frac{1}{6}). This gives (x^2-7x-30=0), so (x=10).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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