0 reads0 ratings0 helpful
The sum of squares of two consecutive positive integers is (1513). What is the smaller integer?
Advertisement
Answer and explanation
Correct answer: (27)
If the smaller integer is (x), then (x^2+(x+1)^2=1513), giving (x=27). Write consecutive integers as (x) and (x+1).
Frequently asked questions
What is the correct answer to this question?
(27)
Why is this the correct answer?
If the smaller integer is (x), then (x^2+(x+1)^2=1513), giving (x=27). Write consecutive integers as (x) and (x+1).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement