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The sum of squares of two consecutive positive integers is (1201). What is the smaller integer?दो लगातार धनात्मक पूर्णांकों के वर्गों का योग (1201) है। छोटा पूर्णांक क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (24)(24)
If the smaller integer is (x), then (x^2+(x+1)^2=1201), giving (x=24). Write consecutive integers as (x) and (x+1).छोटा पूर्णांक (x) हो तो (x^2+(x+1)^2=1201), जिससे (x=24) मिलता है। लगातार पूर्णांकों को (x) और (x+1) लिखें।
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