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The product of two consecutive positive integers is 56. Which quadratic equation represents this situation if the smaller integer is \(x\)?
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Answer and explanation
Correct answer: \(x^2+x-56=0\)
The consecutive integers are \(x\) and \(x+1\). Thus, \(x(x+1)=56\), which gives \(x^2+x-56=0\). Option B incorrectly represents the second integer as \(x-1\). Exam tip: translate each word condition into algebra first.
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What is the correct answer to this question?
\(x^2+x-56=0\)
Why is this the correct answer?
The consecutive integers are \(x\) and \(x+1\). Thus, \(x(x+1)=56\), which gives \(x^2+x-56=0\). Option B incorrectly represents the second integer as \(x-1\). Exam tip: translate each word condition into algebra first.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.
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