0 reads0 ratings0 helpful
The product of two consecutive positive even integers is 288. What is the larger integer?
Advertisement
Answer and explanation
Correct answer: 18
Let the smaller even integer be \(x\). The next consecutive even integer is \(x+2\). Thus, \(x(x+2)=288\), giving \(x^2+2x-288=0\). The positive solution is \(x=16\), so the larger integer is \(16+2=18\). Exam tip: consecutive even integers differ by 2, not 1.
Frequently asked questions
What is the correct answer to this question?
18
Why is this the correct answer?
Let the smaller even integer be \(x\). The next consecutive even integer is \(x+2\). Thus, \(x(x+2)=288\), giving \(x^2+2x-288=0\). The positive solution is \(x=16\), so the larger integer is \(16+2=18\). Exam tip: consecutive even integers differ by 2, not 1.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement