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The product of the numbers that are 2 and 3 more than a positive number is 306. What is the original number?

Answer and explanation

Correct answer: 15

Let the original number be \(x\). Then \((x+2)(x+3)=306\), which gives \(x^2+5x-300=0\). Factoring, \((x+20)(x-15)=0\), so \(x=-20\) or \(x=15\). Since the question specifies a positive number, the original number is \(15\). Exam tip: Form the algebraic equation first and then select the root that satisfies the condition in the question.

Related tags

Quadratic EquationsWord ProblemsNumber ApplicationsFactorisationPositive RootsWord Problems And ApplicationsMathematicsClass 10 Mcq

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