Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

The difference between the length and breadth of a rectangle is 7 cm, and its area is 330 square cm. What is the perimeter of the rectangle?

Advertisement

Answer and explanation

Correct answer: 74 cm

Let the breadth be \(x\) cm. Then the length is \(x+7\) cm. Using the area, \(x(x+7)=330\), so \(x^2+7x-330=0\). Factoring gives \((x-15)(x+22)=0\). Thus \(x=15\) cm, since the negative root \(-22\) is not physically meaningful, and the length is \(22\) cm. Therefore, the perimeter is \(2(15+22)=74\) cm. Exam tip: In geometry word problems, reject any negative root because a length cannot be negative.

Related tags

Quadratic EquationsRectanglePerimeterWord Problems

Frequently asked questions

What is the correct answer to this question?

74 cm

Why is this the correct answer?

Let the breadth be \(x\) cm. Then the length is \(x+7\) cm. Using the area, \(x(x+7)=330\), so \(x^2+7x-330=0\). Factoring gives \((x-15)(x+22)=0\). Thus \(x=15\) cm, since the negative root \(-22\) is not physically meaningful, and the length is \(22\) cm. Therefore, the perimeter is \(2(15+22)=74\) cm. Exam tip: In geometry word problems, reject any negative root because a length cannot be negative.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement