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In an examination, the number of students is \(x\), and each student is given \((x-11)\) questions. If the total number of questions given is \(1092\), how many students are there?

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Answer and explanation

Correct answer: 39

The total number of questions gives \(x(x-11)=1092\). Thus, \(x^2-11x-1092=0\), which factors as \((x-39)(x+28)=0\). Therefore, \(x=39\) or \(x=-28\). Since the number of students cannot be negative, the valid answer is 39. Check: \(39\times(39-11)=39\times28=1092\). In such word problems, always reject a negative root when the variable represents a count.

Related tags

Quadratic EquationsWord ProblemsApplication ProblemsFactorisationExam Arrangement

Frequently asked questions

What is the correct answer to this question?

39

Why is this the correct answer?

The total number of questions gives \(x(x-11)=1092\). Thus, \(x^2-11x-1092=0\), which factors as \((x-39)(x+28)=0\). Therefore, \(x=39\) or \(x=-28\). Since the number of students cannot be negative, the valid answer is 39. Check: \(39\times(39-11)=39\times28=1092\). In such word problems, always reject a negative root when the variable represents a count.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Word Problems and Applications.

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