यदि किसी ग्राफ के शून्यक (-1), (3), और (8) हैं, तो ग्राफ (x)-अक्ष को किन बिंदुओं पर काटेगा?
If the zeroes of a graph are (-1), (3), and (8), at which points will it cut the (x)-axis?
Explanation opens after your attempt
A. ((-1,0)), ((3,0)), ((8,0))
Concept
Use the zeroes as (x)-coordinates and take (y=0). So the intersection points are ((-1,0)), ((3,0)), and ((8,0)).
Why this answer is correct
The correct answer is A. ((-1,0)), ((3,0)), ((8,0)). Use the zeroes as (x)-coordinates and take (y=0). So the intersection points are ((-1,0)), ((3,0)), and ((8,0)).
Exam Tip
शून्यकों को (x)-निर्देशांक बनाकर (y=0) लिया जाता है। इसलिए कटाव बिंदु ((-1,0)), ((3,0)), और ((8,0)) होंगे।
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